Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    For the following half cell reactions,\[E{}^\circ \]values are also given \[M{{n}^{2+}}+2{{H}_{2}}O\xrightarrow[{}]{{}}Mn{{O}_{2}}+4{{H}^{+}}+2{{e}^{-}};\] \[E{}^\circ =-1.23V\] \[MnO_{4}^{-}+4{{H}^{+}}+3{{e}^{-}}\xrightarrow[{}]{{}}Mn{{O}_{2}}+2{{H}_{2}}O;\] \[E{}^\circ =+1.70V\] Select correct statements

    A) \[M{{n}^{2+}}\]reacts with\[MnO_{4}^{-}\]in acid solution to form\[Mn{{O}_{2}}\]

    B) \[Mn{{(Mn{{O}_{4}})}_{2}}\]is stable in acid solution

    C) \[Mn{{O}_{2}}\]disproporttbnates to\[M{{n}^{2+}}\]and \[MnO_{4}^{-}\] in acid solution

    D)  None of the above

    Correct Answer: A

    Solution :

     \[2MnO_{4}^{-}+3M{{n}^{2+}}+2{{H}_{2}}O\xrightarrow[{}]{{}}5Mn{{O}_{2}}+4{{H}^{+}};\] \[E{}^\circ =0.47\,V\] Thus, cell reaction in which\[M{{n}^{2+}}\]on reaction with\[MnO_{4}^{-}\]forms\[Mn{{O}_{2}}\]in acidic medium.


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