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Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    Two liquids X and Y form an ideal solution at 300K, vapour pressure of the solution containing 1 mole of X and 3 moles of Y is 550 mm Hg. At the same temperature, if 1 mole of V is further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mm Hg) of X and V in their pure states will be respectively

    A)  200 and 300

    B)  300 and 400

    C)  400 and 600

    D)  500 and 600

    Correct Answer: C

    Solution :

     \[{{\rho }_{total}}=p_{A}^{o}.{{x}_{A}}+p_{B}^{o}.{{x}_{B}}\] \[550=p_{A}^{o}\times \frac{1}{4}+p_{B}^{o}\times \frac{3}{4}\] \[p_{A}^{o}+3p_{B}^{o}=2200\]                    ?(i) When 1 mole of y is further added to the solution \[560=p_{A}^{o}\times \frac{1}{5}+p_{B}^{o}\times \frac{4}{5}\] \[p_{A}^{o}+4p_{B}^{o}=2800\]    ...(ii) On subtraction, (ii) - (i) \[p_{B}^{o}=2800-200=600\] On putting the value of\[p_{B}^{o}\]Eq. (i) \[p_{A}^{o}+3\times 600=220\] \[p_{A}^{o}=2200-1800=400\] On putting the value of\[p_{B}^{o}\]in Eq. (i) \[p_{A}^{o}+3\times 600=220\] \[{{p}_{{{A}_{0}}}}=2200-1800=400\]


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