A) 12.63 g
B) 17.95 g
C) 126.3 g
D) 179.5 g
Correct Answer: C
Solution :
\[C(s)+{{O}_{2}}(g)\xrightarrow[{}]{{}}C{{O}_{2}}(g)\] \[\Delta H_{f}^{o}(C{{O}_{2}})=-\text{ }95\text{ }kcal\text{ }mo{{l}^{-1}}\] \[=-95\]kcal/12g of carbon Thus, carbon required for 1000 kcal of heat \[=\frac{12\times 1000}{95}\] \[=126.3g\]
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