A) 3-methyl butanoic acid
B) cis-2-butene
C) isopropyi amine
D) 1-methyl butanamine
Correct Answer: D
Solution :
1-methyul butanamine, \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}-\underset{*}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{CH}}}\,-N{{H}_{2}}\] has one chiral carbon so, it can exist in enantiomeric forms.
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