Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    Light of wavelength K = 4000 A and intensity \[100\text{ }W/{{m}^{2}}\]is incident On a plate of threshold frequency\[5.5\times {{10}^{14}}\]Hz. Find the number of photons incident \[{{m}^{2}}\]per sec.

    A)  \[{{10}^{21}}\]               

    B)  \[3.0\times {{10}^{19}}\]

    C)  \[2.02\times {{10}^{20}}\]      

    D)  \[2.02\times {{10}^{21}}\]

    Correct Answer: C

    Solution :

     Let number of photons emitted per second be\[n\]. Then intensity\[=100\text{ }W/{{m}^{2}}\] \[\frac{nhc}{\lambda }=100\] \[n=\frac{100\times \lambda }{hc}\] \[=\frac{100\times 4000\times {{10}^{-10}}}{hc}\] \[=\frac{100\times 4000\times {{10}^{-10}}}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[=2.02\times {{10}^{20}}\]


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