A) 6m
B) 2/9 m
C) 2/3m
D) 18m
Correct Answer: D
Solution :
It is given that acceleration due to gravity on plane. A is 9 times the acceleration due to gravity on planet B i.e., \[{{g}_{A}}=9{{g}_{B}}\] ?..(i) From third equation of motion \[{{v}^{2}}=2gh\] At planet \[A,{{h}_{A}}=\frac{{{v}^{2}}}{2{{g}_{A}}}\] ...(ii) At planet \[S,{{H}_{B}}=\frac{{{v}^{2}}}{2{{g}_{B}}}\] ...(iii) Dividing Eq. (ii) by Eq. (iii) we have \[\frac{{{h}_{A}}}{{{h}_{B}}}=\frac{9{{g}_{B}}}{{{g}_{A}}}\] From Eq. (i), \[{{g}_{A}}=9{{g}_{B}}\] \[\therefore \] \[\frac{{{h}_{A}}}{{{h}_{B}}}=\frac{{{g}_{B}}}{9{{g}_{B}}}=\frac{1}{9}\] or \[{{h}_{B}}=9{{h}_{B}}=9\times 2=18\,m\] \[(\therefore {{h}_{A}}=2m)\]
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