A) between\[\frac{3}{2}\]and 2
B) \[\frac{1}{2}\]
C) more than\[\frac{1}{2}\]
D) less than\[\frac{1}{2}\]
Correct Answer: D
Solution :
Using the relation. \[{{T}_{1}}{{V}_{1}}^{\gamma -1}={{T}_{2}}V_{2}^{\gamma -1}\] \[\frac{{{V}_{2}}}{V}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{1-\gamma }}={{\left( \frac{{{T}_{1}}}{2{{T}_{1}}} \right)}^{1-\gamma }}\] Or \[\frac{1}{{{(2)}^{1-\gamma }}}>\frac{1}{2}\]
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