A) \[12\times {{10}^{23}}\]
B) \[26\times {{10}^{23}}\]
C) \[34\times {{10}^{23}}\]
D) \[48\times {{10}^{23}}\]
Correct Answer: D
Solution :
Sodium ferrocyanide,\[N{{a}_{4}}[Fe{{(CN)}_{6}}]\]contains four sodium atoms. Number of Na atoms = Number of moles\[\times \] number of atoms per molecule\[\times \]Avogadro number \[=2\times 4\times 6.023\times {{10}^{23}}\] \[=48\times {{10}^{23}}\]atoms
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