Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    The rate of reaction \[CC{{l}_{3}}CHO+NO\xrightarrow[{}]{{}}CHC{{l}_{3}}+NO+CO\] Is equal to rate\[=k[CC{{l}_{3}}CHO][NO]\]. If concentration is expressed in\[mol\text{ }{{L}^{-1}},\]the unit of\[k\]is

    A)  \[L\,mo{{l}^{-1}}{{s}^{-1}}\]       

    B)  \[mol\text{ }{{L}^{-1}}{{s}^{-1}}\]  

    C)  \[{{L}^{2}}mo{{l}^{-2}}{{s}^{-1}}\]     

    D)  \[{{s}^{-1}}\]

    Correct Answer: A

    Solution :

     Rate\[=\frac{dx}{dt}=k[CC{{l}_{3}}CHO][NO]\] \[k=\frac{dx}{dt\times [CC{{l}_{3}}CHO][NO]}\] \[=\frac{mol\,{{L}^{-1}}}{{{s}^{-1}}\times mol\,{{L}^{-1}}\times mol\,{{L}^{-1}}}\] \[=L\,mo{{l}^{-1}}{{s}^{-1}}\]


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