Manipal Medical Manipal Medical Solved Paper-2012

  • question_answer
    A current of 5 A is passing through a metallic wire of cross-sectional area\[4\times {{10}^{-6}}{{m}^{2}}\]. If the density of charge carriers of the wire is\[5\times {{10}^{26}}\] \[{{m}^{-3}},\]the drift velocity of the electrons will be

    A)  \[1\times {{10}^{2}}m{{s}^{-1}}\]

    B)  \[1.56\times {{10}^{-2}}m{{s}^{-1}}\]

    C)  \[1.56\times {{10}^{-3}}m{{s}^{-1}}\]

    D)  \[1\times {{10}^{-2}}m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

     Drift velocity, \[{{v}_{d}}=\frac{I}{neA}\] \[\Rightarrow \]\[{{v}_{d}}=\frac{5}{(5\times {{10}^{26}})\times (1.6\times {{10}^{-19}})\times (4\times {{10}^{-6}})}\] \[=1.56\times {{10}^{-2}}m{{s}^{-1}}\]


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