A) \[\frac{1}{2}\]
B) \[\frac{1}{16}\]
C) \[\frac{1}{8}\]
D) \[\frac{1}{32}\]
Correct Answer: D
Solution :
We know that \[n=\frac{t}{T}\] Given, \[t=3000\text{ }yr,\text{ }T=6000\text{ }yr\] \[n=\frac{3000}{600}=5\] Then, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{5}}=\frac{1}{32}\]
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