A) \[SrC{{l}_{3}}\]
B) \[FeC{{l}_{3}}\]
C) \[TiC{{l}_{3}}\]
D) \[VC{{l}_{3}}\]
Correct Answer: A
Solution :
\[ScC{{l}_{3}}\xrightarrow[{}]{{}}S{{c}^{3+}}+3C{{l}^{-}}\]
No unpaired electron so, will show diamagnetic character so will weights less when, weighted in magnetic field.
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