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Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    A weak acid HX has the dissociation constant\[1\times {{10}^{-5}}M\]. It forms a salt\[NaX\]on reaction with alkali. The degree of hydrolysis of 0.1 M solution of\[NaX\]is

    A)  0.0001%        

    B)  0.01%

    C)  0.1%            

    D)  0.15%

    Correct Answer: B

    Solution :

    \[{{X}^{-}}+{{H}_{2}}OHX+O{{H}^{-}}\] \[{{K}_{h}}=\frac{{{10}^{-14}}}{{{10}^{-5}}}\] So, degree of hydrolysis \[x=\sqrt{\frac{{{K}_{h}}}{C}}=\sqrt{\frac{{{10}^{-9}}}{{{10}^{-1}}}}={{10}^{-4}}\] % degree of hydrolysis \[={{10}^{-4}}\times 100=0.01%\]


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