A) 0.3%
B) 0.6%
C) 0.9%
D) \[\frac{4}{3}\pi {{(0.3)}^{3}}\]
Correct Answer: C
Solution :
Error in radius, \[\frac{\Delta r}{r}=0.3%\] Volume of sphere\[=\frac{4}{3}\pi {{r}^{3}}\] \[\therefore \]Error in volume\[=3\times \frac{\Delta r}{r}\] \[=(3\times 0.3)%=0.9%\]
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