Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    The ionization energy of\[L{{i}^{2+}}\]is equal to

    A)  \[9~hcR\]            

    B)  \[6~hcR\]

    C)  \[2~hcR\]           

    D)  \[~hcR\]

    Correct Answer: A

    Solution :

     lonization energy\[=Rch{{Z}^{2}}\] \[Z=3\]for \[L{{i}^{2+}}\] lonization energy \[={{(3)}^{2}}Rch\] \[=9Rch\]


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