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Manipal Medical Manipal Medical Solved Paper-2011

  • question_answer
    A\[2\mu F\]capacitor is charged to 100 V and then its plates are connected by a conducting wire, the heat produced is

    A)  \[1\,J\]                

    B)  \[0.1\,J\]

    C)  \[0.01\,J\]             

    D)  \[0.00\,J\]

    Correct Answer: C

    Solution :

     Here \[C=2\mu F,V=100volt\] Heat produced \[H=\frac{1}{2}C{{V}^{2}}\] \[=\frac{1}{2}(2\times {{10}^{-6}})\times {{(100)}^{2}}\] \[=1\times {{10}^{-2}}J\] \[=0.01J\]


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