Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    A coin is of mass 4.8 kg and radius 1 m rolling on a horizontal surface without sliding with angular velocity 600 rot/min. What is total kinetic energy of the coin?

    A)  \[360\,J\]

    B)  \[1440{{\pi }^{2}}J\]

    C)  \[4000{{\pi }^{2}}J\]

    D)  \[600{{\pi }^{2}}J\]

    Correct Answer: B

    Solution :

      Angular velocity is given by \[\omega =600\text{ }rot/min\] \[=\frac{600\times 2\pi }{60}rad/s\] \[=20\pi \text{ }rad/s\] Kinetic energy of coin which is due to rotation and translation is \[K=\frac{1}{2}I{{\omega }^{2}}+\frac{1}{2}m{{v}^{2}}\] \[=\frac{1}{2}\times \frac{1}{2}m{{r}^{2}}{{\omega }^{2}}+\frac{1}{2}m{{(r\omega )}^{2}}\] \[=\frac{1}{2}\times 4.8\times {{(1)}^{2}}{{(20\pi )}^{2}}+\frac{1}{2}\times 4.8\times {{(20\pi \times 1)}^{2}}\] \[=480{{\pi }^{2}}+960{{\pi }^{2}}\] \[=1440{{\pi }^{2}}J\]


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