A) \[\frac{F}{2}\]
B) zero
C) \[2F\]
D) \[\sqrt{2F}\]
Correct Answer: B
Solution :
From Coulombs law, electric force between two charges is directly proportional to product of charges and inversely proportional to square of distance between them. That is \[F=k\frac{{{q}_{1}}{{q}_{2}}}{{{d}^{2}}}\] where,\[k=\frac{1}{4\pi {{\varepsilon }_{0}}}=\]proportionality constant. If a medium is placed between the charges, then \[F=\frac{1}{4\pi {{\varepsilon }_{0}}K}\frac{{{q}_{1}}{{q}_{2}}}{{{d}^{2}}}\] Since, medium placed between the charges is a metallic plate, so for it \[K=\infty \] Hence, \[F=0\] (zero)
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