A) 4, 4
B) 4, 6
C) 4, 8
D) 4, 2
Correct Answer: A
Solution :
When\[\alpha -\]particle is emitted, the mass number decreases by 4 units and atomic number decreases by 2 units and for\[\beta -\]particle, atomic number is increased by 1 and mass number remains the same. Given reaction is \[_{92}B{{e}^{234}}{{\xrightarrow[{}]{{}}}_{88}}{{Y}^{218}}\] Number of\[\alpha -\]particles \[=\frac{234-218}{4}\] \[=\frac{16}{4}=4\] Decrease in atomic number\[=4\times 2=8\] ie., \[92-8=84\] From atomic number 88, number of\[\beta -\]particles emitted\[=\frac{88-84}{1}=4\] Hence,\[4\alpha \]and\[4\beta -\]particles are emitted.
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