A) \[PO_{4}^{3-}\]
B) \[{{P}_{2}}{{O}_{5}}\]
C) \[{{H}_{3}}P{{O}_{4}}\]
D) \[HPO_{4}^{2-}\]
Correct Answer: D
Solution :
Acid\[-{{H}^{+}}\xrightarrow[{}]{{}}\]conjugate base \[\therefore \] \[{{H}_{2}}PO_{4}^{-}+{{H}^{+}}\xrightarrow[{}]{{}}HPO_{4}^{2-}\] \[\therefore \]\[HPO_{4}^{2-}\]is the conjugate base of\[{{H}_{2}}PO_{4}^{-}\].
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