A) \[{{H}_{2}}+B{{r}_{2}}\xrightarrow[{}]{{}}2HBr\]
B) \[NaBr+HCl\xrightarrow[{}]{{}}NaCl+HBr\]
C) \[HBr+AgN{{O}_{3}}\xrightarrow[{}]{{}}AgBr+HN{{O}_{3}}\]
D) \[2NaOH+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]
Correct Answer: A
Solution :
[b] \[NaBr+HCl\xrightarrow[{}]{{}}NaCl+HBr\] It is a substitution reaction. [c] \[HBr+AgN{{O}_{3}}\xrightarrow[{}]{{}}AgBr+HN{{O}_{3}}\] It is a substitution and precipitation reaction because\[AgBr\]is precipitated during this reaction. [d] \[2NaOH+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}N{{a}_{2}}S{{O}_{4}}+2{{H}_{2}}O\] It is a neutralisation reaction because acid and base are reacting to produce salt and \[{{H}_{2}}O\]. [a] \[\overset{0}{\mathop{{{H}_{2}}}}\,+\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow[{}]{{}}2{{H}^{+}}B{{r}^{-}}\] This is oxidation reduction reaction because during this reaction oxidation number are changing.
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