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Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    Calculate the free energy change for the following reaction at 300 K. \[2CuO(s)\xrightarrow[{}]{{}}C{{u}_{2}}O(s)+\frac{1}{2}{{O}_{2}}(g)\] Given, \[\Delta H=145.6\text{ }kJ\text{ }mo{{l}^{-1}}\] and \[\Delta S=116\text{ }J{{k}^{-1}}mo{{l}^{-1}}\]

    A)  \[110.8\text{ }kJ\text{ }mo{{l}^{-1}}\]  

    B)  \[221.5\text{ }kJ\,mo{{l}^{-1}}\]

    C)  \[55.4\text{ }kJ\text{ }mo{{l}^{-1}}\]   

    D)  \[145.6\text{ }kJ\text{ }mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

     \[\Delta G=\Delta H-T\Delta S\] \[=145.6\times {{10}^{3}}-300\times 116\] \[=145.6\times {{10}^{3}}-34.8\times {{10}^{3}}\] \[=110.8\times {{10}^{3}}Jmo{{l}^{-1}}\] \[=110.8\text{ }kJ\,mo{{l}^{-1}}\]


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