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Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    The electrons identified by quantum number\[n\]and\[l\]
    (i) \[n=4,Z=l\]
    (ii) \[n=4,l=0\]
    (iii) \[n=3,l=2\]     
    (iv) \[n=3,l=1\]
    Can be placed in order of increasing energy from the lowest to highest as

    A)  (iv) < (ii) < (iii) < (i)

    B)  (ii) < (i^) < (i) < (iii)

    C)  (i) < (iii) < (ii) < (iv)

    D)  (iii) < (i) < (iv) < (ii)

    Correct Answer: A

    Solution :

     Greater the value of\[n+l,\]more will be the energy of electron. If the two electrons have same value for\[(n+l)\]then one with lower value of n should be filled first because it possesses lower energy. (i) \[n=4,l=1\therefore n+l=4+1=5\] (ii) \[n=4,l=0\therefore n+l=4+0=4\] (iii) \[n=3,l=2\therefore n+l=3+2=5\] (iv) \[n=3,l=1\therefore n+l=3+1=4\] \[\therefore \]The correct order of energy is (iv) < (ii) < (iii) < (i)


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