| (i) \[{{(C{{H}_{3}})}_{3}}CBr\] |
| (ii) \[{{({{C}_{6}}{{H}_{5}})}_{2}}CHBr\] |
| (iii) \[{{({{C}_{6}}{{H}_{5}})}_{2}}C(C{{H}_{3}})Br\] |
| (iv) \[{{(C{{H}_{3}})}_{2}}CHBr\] |
| (v) \[{{C}_{2}}{{H}_{5}}Br\] |
A) (ii)> (i) > (iii) > (v) > (iv)
B) (i)>(m)>(v)>(ii)>(iv)
C) (v)> (i)> (ii) > (iv) > (iii)
D) (iii)> (ii)> (i) > (iv) > (v)
Correct Answer: D
Solution :
In\[{{S}_{N}}1\](Unimolecular nucleophilic substitution) reactions, Rate \[\propto \] [substrate] Rate determining step is the formation of carbocation and depends on the stability of carbocation formed. The stability of carbocations follow the order \[{{({{C}_{6}}{{H}_{5}})}_{2}}{{C}^{+}}(C{{H}_{3}})>{{({{C}_{6}}{{H}_{5}})}_{2}}\overset{+}{\mathop{C}}\,H>{{(C{{H}_{3}})}_{3}}{{C}^{+}}\] \[{{(C{{H}_{3}})}_{2}}\overset{+}{\mathop{C}}\,H>C{{H}_{3}}CH_{2}^{+}\] Thus, the order of reactivity towards\[{{S}_{N}}1\] reaction is (iii) > (ii) > (i) > (iv) > (v)
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