question_answer

Excess of\[KI\]reacts with\[CuS{{O}_{4}}\]solution and then\[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]solution is added to it. Which of the statements is incorrect for this reaction?

A) \[C{{u}_{2}}{{I}_{2}}\]is formed

B) \[Cu{{I}_{2}}\] is formed

C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]is oxidised

D)  Evolved\[{{I}_{2}}\]is reduced

Correct Answer: B

Solution :

 \[CuS{{O}_{4}}+2KI\xrightarrow[{}]{{}}{{K}_{2}}S{{O}_{4}}+Cu{{I}_{2}}\] \[2Cu{{I}_{2}}\xrightarrow[{}]{{}}C{{u}_{2}}{{I}_{2}}+{{I}_{2}}\] Hence,\[Cu{{I}_{2}}\]is not formed.