A) aqueous\[HCl\]and heat
B) aqueous\[NaOH\]and heat
C) acidified\[KMn{{O}_{4}}\]
D) bromine water
Correct Answer: B
Solution :
Acetamide and ethylamine can be distinguished by heating with\[NaOH\]solution when acetamide liberates NH3 but ethylamine does not. \[C{{H}_{3}}CON{{H}_{2}}+NaOH\xrightarrow[{}]{\Delta }C{{H}_{3}}COONa+N{{H}_{3}}\] \[C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}+NaOH\xrightarrow[{}]{{}}\] No reaction
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