Manipal Medical Manipal Medical Solved Paper-2010

  • question_answer
    A photocell is illuminated by a small bright Source placed 2 m away. When the same source of light is placed 4m away, the electrons emitted by photo-cathode in one second

    A)  carry one quarter of their previous energy

    B)  carry one quarter of their previous momentum

    C)  are half numerous

    D)  are one quarter numerous

    Correct Answer: D

    Solution :

     When light falls normally on a surface, the illuminance is maximum. If from a light source of luminous intensity\[(I),\]light is falling normally on a surface distant r from the source, then illuminance is \[E=\frac{I}{{{r}^{2}}}\] Given, \[{{r}_{1}}=2m,{{r}_{2}}=4m\] \[\therefore \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{r_{2}^{2}}{r_{1}^{2}}\] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{(4)}^{2}}}{{{(2)}^{2}}}=4\Rightarrow {{E}_{2}}=\frac{{{E}_{1}}}{4}\] Hence, electrons emitted by photo cathode in one second are one quarter numerous.


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