A) 5 N
B) 8.25 N
C) 0.25 N
D) 1.0 N
Correct Answer: C
Solution :
If a constant force F is applied on a body for a short interval of time\[\Delta t,\] then the impulse of this force is\[F\Delta t\]. When mass of body is m, an applying force F, for a time interval\[\Delta t,\]the body suffers a velocity change\[\Delta v,\]then \[F=ma=m\frac{\Delta v}{\Delta t}\Rightarrow F\Delta t=m\Delta v\] Given,\[F=x\]newton. At \[\Delta t=2s,{{v}_{1}}=2m/s,\] \[{{v}_{2}}=3m/s,\text{ }m=0.5kg\] \[\therefore \] \[x\times 2=0.5\times 1\] \[\Rightarrow \] \[x=\frac{0.5}{2}=0.25\,N\]
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