A) \[Zn{{H}_{2}}\]
B) \[N{{a}_{2}}Zn{{O}_{2}}\]
C) \[ZnO\]
D) \[Zn{{(OH)}_{2}}\]
Correct Answer: A
Solution :
Excess of sodium hydroxide reacts with zinc to form\[N{{a}_{2}}Zn{{O}_{2}}\]. \[Zn+2NaOH\xrightarrow[{}]{{}}N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\uparrow \]
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