Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    8.2 L of an ideal gas weighs 9.0 g at 300 K and 1 atm pressure. The molecular mass of gas is

    A)  9               

    B)  27

    C)  54              

    D)  81

    Correct Answer: B

    Solution :

     \[\Rightarrow \] \[pV=nRT\] Or \[pV=\frac{w}{M}RT\] \[\therefore \] \[M=\frac{wRT}{pV}\] \[=\frac{9.0\times 0.082\times 300}{1\times 8.2}=27\]


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