A) 4R
B) 8R
C) 16 R
D) 32 R
Correct Answer: C
Solution :
As we know \[R\propto {{T}^{4}}\] \[\therefore \] \[\frac{R}{R}=\frac{{{(273+273)}^{4}}}{{{(273+0)}^{4}}}=\frac{16\times {{(273)}^{4}}}{{{(273)}^{4}}}\] \[R=16\,R\]
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