Manipal Medical Manipal Medical Solved Paper-2009

  • question_answer
    A body of mass 2 kg makes an elastic collision with another body at rest and continues to move in the original direction with one-fourth its original speed. The mass of the second body which collides with the first body is

    A)  2 kg             

    B)  1.2 kg

    C)  3 kg             

    D)  1.5 kg

    Correct Answer: B

    Solution :

    Conservation of linear momentum gives \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}={{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}\] \[\Rightarrow \] \[{{m}_{2}}{{v}_{2}}=\frac{3u}{2}\] Conservation of kinetic energy gives \[\frac{1}{2}{{m}_{1}}u_{1}^{2}+\frac{1}{2}{{m}_{2}}u_{2}^{2}=\frac{1}{2}{{m}_{1}}v_{1}^{2}+\frac{1}{2}{{m}_{2}}v_{2}^{2}\] \[\Rightarrow \] \[{{m}_{2}}v_{2}^{2}=\frac{15{{u}^{2}}}{8}\] ?(ii) Hence, on solving Eqs. (i) and (ii), we get \[{{m}^{2}}=1.2kg\]


You need to login to perform this action.
You will be redirected in 3 sec spinner