A) \[C{{H}_{2}}=CHC{{H}_{3}}\]
B) \[{{H}_{2}}C=CHCl\]
C) \[{{H}_{2}}C=CH{{C}_{2}}{{H}_{5}}\]
D) \[{{H}_{2}}C=CHC{{O}_{2}}C{{H}_{3}}\]
Correct Answer: C
Solution :
In cationic polymerization, carbocations are formed. Greater the stability of the carbocation, more reactive is the alkene. Since, the stability of the intermediate carbocation follows the order \[C{{H}_{3}}-\overset{+}{\mathop{C}}\,H{{C}_{6}}{{H}_{5}}>C{{H}_{3}}\overset{+}{\mathop{C}}\,HC{{H}_{3}}>\] \[C{{H}_{3}}\overset{+}{\mathop{C}}\,HCl>C{{H}_{3}}\overset{+}{\mathop{C}}\,HC{{O}_{2}}C{{H}_{3}}\] Therefore, reactivity decreases in the same order. Thus, styrene is most reactive.
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