A) \[{{e}_{1}}={{e}_{2}}\]
B) \[{{e}_{1}}>{{e}_{2}}\]
C) \[{{e}_{1}}<{{e}_{2}}\]
D) \[{{e}_{1}}>/{{e}_{2}}\]
Correct Answer: C
Solution :
When the switch is closed, the current grows in the circuit but due to self-inductance of the inductor the growth is slow. On disclosing the switch the current suddenly decreases to zero on account of the infinite resistance of the circuit. Thus, rate of growth of the current is lower as compared to the rate of decay.
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