A) \[(1/n)\]
B) \[1/(n+1)\]
C) \[n/(n+1)\]
D) \[(n+1)/n\]
Correct Answer: C
Solution :
\[I=\frac{E}{r+nr}\] \[=\frac{E}{r(n+1)}\] \[V=E-Ir\] \[=E-\frac{E}{r(n+1)}r=\frac{nE}{n+1}\] \[\therefore \] \[\frac{V}{E}=\frac{n}{n+1}\]
You need to login to perform this action.
You will be redirected in
3 sec
