A) \[1.27\overset{o}{\mathop{\text{A}}}\,\]
B) \[3.59\overset{o}{\mathop{\text{A}}}\,\]
C) \[2.54\overset{o}{\mathop{\text{A}}}\,\]
D) \[3.81\overset{o}{\mathop{\text{A}}}\,\]
Correct Answer: B
Solution :
Here, \[r=1.27\overset{o}{\mathop{\text{A}}}\,\] \[=1.27\times {{10}^{-10}}m\] \[r=\frac{a\sqrt{2}}{4}\] Or \[a=\frac{4r}{\sqrt{2}}\] \[\therefore \] \[a=\frac{4\times 1.27\times {{10}^{-10}}}{\sqrt{2}}m\] \[=3.59\times {{10}^{-10}}m=3.59\overset{o}{\mathop{\text{A}}}\,\]
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