A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{3}{4}\]
D) \[\frac{3}{7}\]
Correct Answer: B
Solution :
Let\[l=\]side of the tube \[x=\]side of cube immersed in water \[l-x=\]side of cube immersed in liquid According to law of floatation, \[{{l}^{3}}\times 0.9\times {{10}^{3}}\times g=({{l}^{2}}\times x)\times 1000\,g\] \[+{{l}^{2}}(l-x)\times 0.7\times {{10}^{3}}g\] \[l\times 0.9=x+(l-x)\times 0.7\] Or \[0.3x=0.2l\] Or \[\frac{x}{l}=\frac{2}{3}\]
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