question_answer

\[{{H}_{2}}O\]is dipolar, whereas\[Be{{F}_{2}}\]is not. It is because

A)  the electronegativity of F is greater than that of 0

B) \[{{H}_{2}}O\]involves hydrogen bonding whereas \[Be{{F}_{2}}\]is a discrete molecule

C)  \[{{H}_{2}}O\]is linear and\[Be{{F}_{2}}\]is angular

D)  \[{{H}_{2}}O\]is angular and\[Be{{F}_{2}}\]is linear

Correct Answer: D

Solution :

 The structure of\[{{H}_{2}}O\]is angular V-shape and has\[s{{p}^{3}}-\]hybridisation and bond angle is 105°. Its dipole moment value is positive or more than zero. but in\[Be{{F}_{2}},\]structure is linear due to\[sp-\]hybridisation\[(\mu =0)\] Thus, due to\[\mu >0,{{H}_{2}}O\]is dipolar and due to \[\mu =0,\text{ }Be{{F}_{2}}\]is non-polar.