Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    The dimensions of universal gravitational constant are

    A)  \[[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]

    B)  \[[M{{L}^{2}}{{T}^{-1}}]\]

    C)  \[[{{M}^{-2}}{{L}^{3}}{{T}^{-2}}]\]

    D)  \[[{{M}^{-2}}{{L}^{2}}{{T}^{-1}}]\]

    Correct Answer: A

    Solution :

     Key Idea: Substitute the dimensions for the quantities involved in an expression written for gravitational constant. According to Newtons law of gravitation, the force of attraction between two masses\[{{m}_{1}}\]and \[{{m}_{2}}\]separated by a distance r is, \[F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\Rightarrow G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\] Substituting the dimensions for the quantities on the right hand side, we obtain dimensions of\[G=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}\] \[=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]


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