A) \[{{n}^{2}}/R\]
B) \[R/{{n}^{2}}\]
C) \[R/n\]
D) \[nR\]
Correct Answer: A
Solution :
Equivalent resistance of n resistances each of r ohm in parallel is given by \[\frac{1}{R}=\frac{1}{r}+\frac{1}{r}+.....+n\,times=\frac{n}{r}\] So, \[r=nR\] When these resistances are connected in series, effective resistance is \[R=r+r+......+n\text{ }times=nr\] \[\therefore \] \[R=n(nR)={{n}^{2}}R\]
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