A) \[1\times {{10}^{-27}}\]
B) \[1\times {{10}^{-3}}\]
C) \[1\times {{10}^{-7}}\]
D) \[1\times {{10}^{-2}}\]
Correct Answer: B
Solution :
\[BaC{{l}_{2}}\]is a ternary electrolyte. \[BaC{{l}_{2}}=\underset{s}{\mathop{B{{a}^{2+}}}}\,+\underset{2s}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{sp}}=[B{{a}^{2+}}]+{{[2C{{l}^{-}}]}^{2}}\] \[=[s]{{[2s]}^{2}}\] \[{{K}_{sp}}=4{{s}^{3}}\] \[{{K}_{sp}}=4{{s}^{3}}\]where\[s=\]molar solubility \[4{{s}^{3}}=4\times {{10}^{-9}}\] (given) or \[s={{10}^{-3}}M\]
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