Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    To make the frequency double of a spring oscillator, we have to:

    A)  reduce the mass to one-fourth

    B)  quardruple the mass

    C)  double the mass

    D)  half the mass

    Correct Answer: A

    Solution :

     The frequency of spring oscillator is \[v=\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] \[\Rightarrow \] \[v\propto \sqrt{\frac{1}{m}}\] Hence, \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\] Or \[\frac{{{m}_{2}}}{{{m}_{1}}}={{\left( \frac{{{v}_{1}}}{{{v}_{2}}} \right)}^{2}}={{\left( \frac{v}{2v} \right)}^{2}}=\frac{1}{4}\] \[{{m}_{2}}=\frac{{{m}_{1}}}{4}\]


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