A) 0.1 J
B) 0.3J
C) 0.5 J
D) 0.42 J
Correct Answer: D
Solution :
The kinetic energy of sphere while rolling on an inclined plane is given by \[{{E}_{K}}=\]Translational kinetic energy\[+\] Rotational kinetic energy \[=\frac{1}{2}m{{v}^{2}}+\frac{1}{2}I{{\omega }^{2}}\] \[{{E}_{K}}=\frac{1}{2}\times 2\times {{(0.5)}^{2}}+\frac{1}{2}\times \frac{2}{3}\times 2\times \] \[{{(0.1)}^{2}}\times {{\left( \frac{0.5}{0.1} \right)}^{2}}\] \[=0.25+0.17=0.42\text{ }J\]
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