Manipal Medical Manipal Medical Solved Paper-2005

  • question_answer
    In the electrolysis of water, one faraday of electrical energy would evolve:

    A)  one mole of oxygen

    B)  one g atom of oxygen

    C)  8 g of oxygen

    D)  22.4 litres of oxygen

    Correct Answer: C

    Solution :

     Hydrolysis of water can be represented by the following equations- \[2{{H}_{2}}O{{O}_{2}}+4{{H}^{+}}+4{{e}^{-}}\] \[\because \] 4 Faraday of charge liberate\[{{O}_{2}}=32\text{ }g\] \[\therefore \]1 Faraday of charge liberate, \[{{O}_{2}}=\frac{32}{4}\] \[=8g\]


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