A) \[4.07\times {{10}^{4}}\,V\]
B) \[8.2\times {{10}^{4}}\,V\]
C) \[8.2\times {{10}^{3}}\,V\]
D) \[4.07\times {{10}^{5}}\,V\]
Correct Answer: B
Solution :
\[\lambda =\frac{h}{\sqrt{2mqv}}\] \[{{({{10}^{-13}})}^{2}}=\frac{{{(6.6\times {{10}^{-34}})}^{2}}}{2\times 1.67\times {{10}^{-27}}\times 1.6\times {{10}^{-19}}V}\] \[V=8.2\times {{10}^{4}}Volt.\]
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