A) \[9.8\times {{10}^{10}}N/{{m}^{2}}\]
B) \[10.2\times {{10}^{10}}N/{{m}^{2}}\]
C) \[0.98\times {{10}^{10}}N/{{m}^{2}}\]
D) \[8.4\times {{10}^{10}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
Bulk modulus \[B=-\frac{\Delta P}{\frac{-\Delta V}{V}}\] \[\frac{-\Delta V}{V}=\frac{0.01}{100}={{10}^{-4}}\] \[\Delta P=\]pressure of water\[h\rho g\] \[={{10}^{3}}\times 1\times {{10}^{3}}\times 9.8\] \[\Delta P=9.8\times {{10}^{6}}\] \[B=\frac{9.8\times {{10}^{6}}}{{{10}^{-4}}}\] \[=9.8\times {{10}^{10}}N/{{m}^{2}}\]
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