A) \[\left( \frac{2+2\sqrt{3}}{3} \right)\hat{i}-\frac{2}{3}\hat{j}\]
B) \[4\hat{i}\]
C) \[\left( \frac{2-2\sqrt{3}}{3} \right)\hat{i}-\frac{1}{3}\hat{j}\]
D) None of the above
Correct Answer: A
Solution :
Here, \[{{m}_{1}}=1\,kg,{{\overrightarrow{v}}_{1}}=2\hat{i}\] \[{{m}_{2}}=2\,kg\,{{\overrightarrow{v}}_{2}}=2\cos 30\hat{i}-2\sin 30\hat{j}\] \[{{\overrightarrow{v}}_{cm}}=\frac{{{m}_{1}}{{\overrightarrow{v}}_{1}}+{{m}_{2}}{{\overrightarrow{v}}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{1\times 2\hat{i}+2(2\cos 30\hat{i}-2\sin 30\hat{J})}{1+2}\] \[=\frac{2\hat{i}+2\sqrt{3}\hat{i}-2\hat{j}}{3}=\left( \frac{2+2\sqrt{3}}{3} \right)\hat{i}-\frac{2}{3}\hat{j}\]
You need to login to perform this action.
You will be redirected in
3 sec
