A) 5 m/s
B) 14 m/s
C) 175 m/s
D) 10 m/s
Correct Answer: D
Solution :
\[F=\frac{-\partial u\,\hat{i}}{\partial x}\frac{-\partial u\,\hat{j}}{\partial y}\] \[=7\hat{i}-24\hat{j}\] \[\therefore \] \[{{a}_{x}}=\frac{{{F}_{x}}}{m}=\frac{7}{5}=1.4\,m/{{s}^{2}},\]along positive\[x-\]axis \[{{a}_{y}}=\frac{{{F}_{y}}}{m}=-\frac{24}{5}\] =4.8 m/s along negative y-axis \[\therefore \] \[{{\upsilon }_{x}}={{a}_{x}}t=1.4\times 2=2.8\,m/s\] and \[{{\upsilon }_{y}}=4.8\times 2=9.6\,m/s\] \[\therefore \] \[\upsilon =\sqrt{\upsilon _{x}^{2}+\upsilon _{y}^{2}}=10m/s\]
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