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Manipal Medical Manipal Medical Solved Paper-2005

  • question_answer
    A particle moves with ,a velocity\[(5\hat{i}-3\hat{j}+6\hat{k})\] m/s under the influence of a constant force \[\overrightarrow{F}=10\hat{i}+10\hat{j}+12\hat{k}N.\]The instantaneous power applied to the particle is:

    A)  200 J/s       

    B)  40 J/s

    C)  140 J/s        

    D)  170 J/s

    Correct Answer: C

    Solution :

     \[\overrightarrow{V}=(5\hat{i}-3\hat{j}+6\hat{k})m/s\] \[\overrightarrow{F}=(10\hat{i}+10\hat{j}+20\hat{k})N\] \[\therefore \]Power \[\overrightarrow{P}=\overrightarrow{F}.\overrightarrow{v}\] \[=(10\hat{i}+10\hat{j}+20\hat{k}).(5\hat{i}-3\hat{j}+6\hat{k})\] \[=50-30+120\] \[=140\,W\]


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