A) 20%
B) 25%
C) 35 %
D) 15%
Correct Answer: A
Solution :
\[\frac{M}{L}\lg =\mu \frac{M}{L}(L-l)g\] \[l=(L-l)\mu \] \[\frac{l}{L}=\frac{\mu }{1+\mu }\] \[=\frac{0.25}{1.25}=\left( \frac{1}{5}\times 1000 \right)%\] \[=20%\]
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